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At first glance it seems that the shortest
distance between A and B is the straight way along the sides of the
box, i.e. 1 unit up, 30 units along the top side of the box and then
11 units down the opposite side - 42 units in total. But as it was
stated in the hint the shortest distance between A and B is less than
42.
To find the shortest distance out it is useful to unfold some sides of
the box into a 2D model. If to unfold them as shown in the lower right
corner of the illustration, we get a right triangle where the
hypotenuse AB is the distance between the two spots. It equals square
root of (AC2 + BC2). AC is 32 units long (1 + 30
+ 1) and BC is 24 units long (6 + 12 + 6). Thus the distance AB equals
square root (322 + 242) = square root of 1600 or
40.! |
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